Question

sin 65in/cos25+cos32/s58+sin28 sec 62+cosec230

Answer 1

$\frac{sin65^o}{cos25^o} + \frac{cos32^o}{sin58^o} + \frac{sin28^o}{sec62^o} + cosec230^o$

$\frac{sin(90-25)}{cos25^o} + \frac{cos(90-58)}{sin58^o} + \frac{sin(90-62)}{sec62^o} + cosec230^o$

$\frac{cos25^o}{cos25^o} + \frac{sin58^o}{sin58^o} + \frac{cos62^o}{sec62^o} + cosec230^o$

$1 + 1 + cos^262^o + cosec230^o$

= 2 + 0.22 + (-1.3)

= 2.22 - 1.3

= 0.92