Question

sin ⁶A/2 + cos ⁶A/2 = ¼(1+ cos²A)​

Answer 1

Answer:

Explanation:

Given: sin(2cos−1(45))

Use the identity sin(2A)=2sin(A)cos(A)

2sin(cos−1(45))cos(cos−1(45))

The cosine of its inverse yields its argument:

2sin(cos−1(45))(45)

Perform the multiplication:

85sin(cos−1(45))

Use the identity #sin(A) = +-sqrt(1-cos^2(A))

±85√1−cos2(cos−1(45))

Again, the cosine of its inverse yields its argument:

±85√1−(45)2

±85√2525−1625