Math, asked by charishma1761, 10 months ago

sin^6o+cos^6o=1-3 sin²o cos²o

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Answered by sandy1816

5

Answer:

your answer attached in the photo

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Answered by Anonymous

1

Solution →

Answer is in the attachment.

Formulas used →

a³+b³ = (a+b)(a²-ab+b²)
sin²A+Cos²A = 1
a²+b² = (a+b)²-2ab

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