Question

sin^6x+cos^6x+3sin^2cos^2=1​

Answer 1

Answer:

we know

sin²∅ + cos²∅ = 1

cubing both sides

we get

sin^6∅ + cos^6∅ + 3sin²∅.cos²∅(sin²∅ + cos²∅) =1

sin^6∅ + cos^6∅ = 1 - 3sin²∅.cos²∅

put this in above question instead of sin^6∅ + cos^6∅

then question become

1 - 3sin∅².cos²∅ + 3sin²∅.cos²∅ = 1

hence shown

hope this will help you