Question

SIN∅=7/5 THEN FIND COS∅ AND TAN∅ .

Answer 1

Step-by-step explanation:

sinø=opp/hyp=7/5

hyp²=opp²+adj²

5²=7²+x²

x²=49-25=24

x=√24=2√6

cosø=adj/hyp=2√6/5

tanø=opp/adj=7/2√6

Answer 2

Answer:

sin =

$\frac{7}{5} = \frac{perpendicular}{hypotenuse}$

so , we can conclude

p = 7x & h= 5x

applying Pythagoras theorem,

${h}^{2} = {b}^{2} + {p}^{2} \\ {(5x)}^{2} = {b}^{2} + {(7x)}^{2} \\ \sqrt{25 {x}^{2} - 49 {x}^{2} } \\ = \sqrt{24} = 2 \sqrt{6}$

now ,

$\cos = \frac{base}{height} = \: \frac{2 \sqrt{6} }{5}$

and

$\tan = \frac{7}{2 \sqrt{6} }$

please , insert theta there if you copy it

(I was unable find the option to insert it)

I think it's correct ,hope helps

Happy New year