sin(75+a)sin(75-a)-cos(15+a)cos(15-a)=0
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Answer:
Step-by-step explanation:
sin(75+a)sin(75-a)-cos(15+a)cos(15-a)
We know that Cos(90-θ) = Sinθ.
=> Sin(75+a)SIn(75-a) - Cos(90 - (75 - a)) .Cos(90 - (75+a))
=> Sin(75+a)SIn(75-a) - Sin(75 - a)Sin(75+a)
= 0.
Hence proved.
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