Question

sin 75° find the value of

Answer 1

sin 75° = sin( 90 - 15 )

cos 15°            since        sin( 90 - A) = cos A

cos 15°  =   $\frac{\sqrt{3} +1}{2\sqrt2}$

sin 75° =     $\frac{\sqrt{3} +1}{2\sqrt2}$

Answer 2

hey mate here is ur Ans
we know that sin(90)=1. and. cos(90)=0

sin(75)=sin(90-15)

=>. sin(90)cos(15)-cos(90)sin(15)
=>. cos(15)

so, as we find sin(75)=cos(15)
now we have to find value of cos(15)

cos (15)= cos(45-30)

cos(45-30)= cos(45)cos(30)+sin(45)sin(30)

=>. (1/√2)(√3/2)+(1/√2)(1/2)
=>. 1/√2(√3+1/2)
=>. (√3+1)/2√2