sin 75° - sin 15°divided by cos 75° + cos 15°
answer with process
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Answer:
tan30=1/√3
Step-by-step explanation:
(sin75°-sin15°)/cos75°+cos15°
since sinA-sinB=2cos[(A+B)/2]sin[(A-B)/2]
and cosA+cosB=2cos[(A+B)/2]cos[(A-B)/2]
(sin75-sin15)/cos75+cos15
2cos[(75+15)/2]sin[(75-15)/2]/2cos[(75+15/2]cos[(75-15)/2]
=2cos[45]sin[30]/2cos[45]cos[30]
=sin30/cos30=tan30
=1/√3
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