Math, asked by Chethanammu, 10 months ago

Sin(7A)+sin(3A)-sinA=sin3A[2cos(4A)+1]

Answers

Answered by sandy1816

1

Step-by-step explanation:

LHS

sin7A+sin3A-sinA

=(sin7a-sinA)+sin3A

=2cos4Asin3A+sin3A

=sin3A(2cos4A+1)

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