Sin^8 A-cos^8 A=(sin^2 A - cos ^2 A) (1-2sin^2 A cos^2 A)
prove krdo koi please
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Step-by-step explanation:
sin^8A-cos^8A
=(sin⁴A)²-(cos⁴A)²
=(sin⁴A+cos⁴A)(sin⁴A-cos⁴A)
={(sin²A)²+(cos²A)²}{(sin²A)²-(cos²A)²}
={(sin²A+cos²A)²-2sin²Acos²A}(sin²A+cos²A)(sin²A-cos²A)
={(1)²-2sin²Acos²A}(1)(sin²A-cos²A)
=(sin²A-cos²A)(1-2sin²Acos²A)
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