sin^8 theta - cos^8 theta = (1-2cos^2 theta) (1-2sin^2 theta cos^2 theta)
Guys can you explain this with explanation pleaseee!!!
Answers
Answer:
Step-by-step explanation
sin^8 a - cos^8 a = (sin^4 a)^2 -(cos^4 a)^2
=( sin^4 a + cos^4 a) (sin^4 a - cos^4 a )
=((sin^2 a)^2+(cos^2 a) ^2) ((sin^2 a)^2- (cos^2 a) ^2)
=( (sin^2 a+cos^2 a)^2 -2 sin^2 a cos^2 a ) ( sin^2 a+cos^2 a)
(sin^2 a-cos^2 a)
= ( 1 - 2 sin^2 a cos^2 a ) (sin^2 a-cos^2 a)
= ( 1 - 2 sin^2 a cos^2 a ) ( 1 - cos^2 a- cos^2 a)
= ( 1 - 2 sin^2 a cos^2 a ) (1- 2 cos^2 a)