Math, asked by superstardhruv, 11 months ago

sin 80 /cos 10 + sin 59 sec 31 evaluate fasttttttttttttttttttttttttt​

Answers

Answered by Abhisheke
6

Answer:

2

Step-by-step explanation:

sin 80 /cos 10 + sin 59 sec 31

=Sin 80/cos(90-80) + sin 59 / cos (90-59)

=sin 80/sin80 + sin59/sin59

=1+1

=2

Answered by ankitkumar84258425
2

Answer:

Step-by-step explanation:

Sin 80= cos (90-80) = cos 10

Sin = 1/ cosec

Sin 59 = 1/ cosec 59

sec 31 = cosec (90-31)

= cosec 59

Therefore, sin 80/ cos 10 + sin 59sec31

​ = cos 10/ cos 10 + 1/ cosec 59 x cosec 59

= 1+1

=> 2(Ans

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