Question

sin 80°/cos 10°+ sin 59° sec 31°​

Answer 1

Answer:

2

Step-by-step explanation:

sinA=cos(90-A)

sin 80°= cos (90-80)

sin 80°=cos10°---------(i)

similary sin 59°=cos 31   °{sinA=cos(90-A)}

sec = 1/cos

therfore sec 31° = 1/cos31° =1/sin 59°

From eq (i) and (ii)

sin 80/ sin 80 + sin 59 *1/ sin 59

= 1+1 = 2

Answer 2

Answer:

sorry ans is worng and also u did it in a wrong method