Math, asked by prachijain24, 5 months ago

sin^8a-cos^8a=(sin^2a-cos^2a)(1-2 sin^2a cos^2a)

Answers

Answered by hg11062005

1

Answer:

LHS = sin⁸ A-cos⁸ A = [(sin⁴ A +cos⁴ A)*(sin⁴ A - cos⁴ A)]

= [(sin⁴ A +cos⁴ A)*{(sin² A + cos² A)*(sin² A - cos² A)]

= [(sin⁴ A +cos⁴ A)* (sin² A - cos² A)]

prachijain24: Thankyou so much

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