sin^8a-cos^8a=(sin^2a-cos^2a)(1-2 sin^2a cos^2a)
Answers
Answered by
1
Answer:
LHS = sin⁸ A-cos⁸ A = [(sin⁴ A +cos⁴ A)*(sin⁴ A - cos⁴ A)]
= [(sin⁴ A +cos⁴ A)*{(sin² A + cos² A)*(sin² A - cos² A)]
= [(sin⁴ A +cos⁴ A)* (sin² A - cos² A)]
prachijain24:
Thankyou so much
Similar questions