sin^8A-cos^8A=(sin²A-cos²A)(1-2sin²A×cos²A)
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LHS = sin⁸ A-cos⁸ A = [(sin⁴ A +cos⁴ A)*(sin⁴ A - cos⁴ A)]
= [(sin⁴ A +cos⁴ A)*{(sin² A + cos² A)*(sin² A - cos² A)]
= [(sin⁴ A +cos⁴ A)* (sin² A - cos² A)]
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= [(sin⁴ A +cos⁴ A)*{(sin² A + cos² A)*(sin² A - cos² A)]
= [(sin⁴ A +cos⁴ A)* (sin² A - cos² A)]
hope this will help you
mark it as brainliest answer
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