Math, asked by srivarshini0101, 8 months ago

sin 8AcosA - sin 6Acos 3A whole divided by Cos 2ACos A - sin 3Asin 4A

Answers

Answered by Anonymous

1

Answer

:Given: A=30∘

To Prove: cosAcos3A−cos3A+sinAsin3A+sin3A=3

Now, L.H.S:cosAcos3A−cos3A+sinAsin3A+sin3A

= cos30cos330−cos90+sin30sin330+sin90

= 23

(23

)3+211+(21)3

= 43+49 = 412 = 3

Step-by-step explanation:

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