sin 8A*cosA - sin 6A*cos 3A whole divided by Cos 2A*Cos A - sin 3A*sin 4A
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:Given: A=30∘
To Prove: cosAcos3A−cos3A+sinAsin3A+sin3A=3
Now, L.H.S:cosAcos3A−cos3A+sinAsin3A+sin3A
= cos30cos330−cos90+sin30sin330+sin90
= 23
(23
)3+211+(21)3
= 43+49 = 412 = 3
Step-by-step explanation:
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