Question

Sin 8pi/3 cos 23pi/6 + cos 13pi/3 sin 35pi/6 = 1/2

prove this ​

Answer 1

Answer:

Step-by-step explanation:

sin 8pi/3 cos 23 pi/6 + cos 13 pi/3 sin 35pi/6

=sin(3pi-pi/3)cos(4pi-pi/6) + cos(4pi + pi/3) sin(6pi-pi/6)

=sin(pi/3). cos(pi/6)+ cos(pi/3) [-sin(pi/6)]

=sin(pi/3).cos(pi/6)-cos(pi/3)sin(pi/6)

=sin(pi/3 - pi/6)[sin(a-b)=sin a cos b - cos a sin b]

=sin(pi/6)

=1/2