Question

sin^8x+cos^8x = 97/128​

Answer 1

Answer:

Giải pt

1) cos^2 (x) = cos (4x/3)

2) cos(3x) + sin(7x) = 2sin^2( pi/4 + 5x/2) - 2cos^2 (9x/2)

3) sin^8 (x) + cos^8 (x) = 97/128

4) 2cos^2 (x/2) -1 = sin(3x)

p/s: ở câu 2) em bđ thành 2cos (6x) (cos(3x) + sin(x)) = 0 thì chịu !

Mong chỉ giáo thêm!!!!

Answer 2

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