Question

sin(90) - 2 cos(45) .sin(45)

Answer 1

sin 90°- 2cos45°. sin45°

sin 90°- 2cos45°.sin(90-45)

sin 90°- 2cos45°.cos45°

sin 90°- 2cos²45°

1 - 2(1/√2)²

1- 2 (1/2)

1- 1 => 0 ans.

Answer 2

Answer:

sin(90) - 2 cos(45) .sin(45) = 0

Step-by-step explanation:

Its easy just substitute the given trigonometric values

sin 90° = 1

cos 45° = 1/√2

sin 45° = 1/√2

So substitute the values and you get

= 1 - 2 x 1/√2 x 1/√2

= 1 - 2/√2 x 1/√2

= 1 - 2/2

= 0

Therefore sin(90) - 2 cos(45) .sin(45) = 0

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