Sin(90-A) /1-tanA+cos(90-A) /1-cotA=sinaA
+cosA
Answers
Answered by
13
let LHS
CosA/1-tanA + SinA/1-CotA
= Cos^2A/cosA-sinA - sin^2A/cosA-sinA
= (sinA+cosA)(cosA-sinA)/(cosA-sinA)
= cosA+ sinA
CosA/1-tanA + SinA/1-CotA
= Cos^2A/cosA-sinA - sin^2A/cosA-sinA
= (sinA+cosA)(cosA-sinA)/(cosA-sinA)
= cosA+ sinA
Answered by
8
Step-by-step explanation:
please mark has brainliest answer
Attachments:
Similar questions