Question

sin (90-A).Cos (90-A) - tam A/1 + tam ²A​

Answer 1

Question↓

sin (90-A).Cos (90-A) - tan A/1 + tam ²A​

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Given↓

We know that

➡sin(90-A)=cosA

➡cos(90-A)=sinA

To Find↓

tam A/1 + tam ²A​

Now,

➡cosA.sinA/tanA

➡cosA.sinA/sinA/cosA

➡cosA.sinA×cosA/sinA

➡cos²A

We have an identity:

↪sin²A+cos²A=1

↪cos²A=1-sin²A

Therefore,

↪cos²A=1-sin²A

LHS=RHS

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