Question

sin(90-A)×cot(90-A)/sin-A=1​

Answer 1

HEY LEARNER ,

HERE IS YOUR ANSWER,

Pre-requisite knowledge [formula]:

• sin ( 90-A ) = cosA
• cos ( 90-A ) = sinA
• tan ( 90-A ) = cotA
• cosec ( 90-A ) = secA
• sec ( 90-A ) = cosecA
• cot ( 90-A ) = tanA

• tanA = $\frac{sinA}{cosA}$

• cotA = $\frac{cosA}{sinA}$

YOUR QUESTION: sin(90-A)×cot(90-A)/sin-A=1​

LHS = cosA x tanA / sinA

       = cosA x ( sinA / cosA ) / sinA

[ cos A gets cancelled ]

      = sinA / sinA

      =1

      =RHS

HOPE IT HELPS

Answer 2

Answer:

1

Step-by-step explanation:

sin(90-A)×cot(90-A)/sin-A

=cosA×tanA/sinA                      [sin(90-A)=cosA & cot(90A)=tanA]

=(cosA×sinA/cosA)/sinA             (cosA cancels cosA from tanA)

=sinA/sinA

=1