Math, asked by armygirl997, 8 months ago

sin(90-A)-sec^2A pls help me​

Answers

Answered by Anonymous
4

Answer:

Type:1

Sin(90-A)-sec^2A

Cos(-A)-sec^2A

CosA-sec^2A

CosA-1/cos^2A

Cos^3A-1/cos^2A

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Type:2

CosA-(1+tan^2A)

CosA-1-tan^2A

CosA-1-sin^2A/cos^2A

Cos^3A-sin^2A-cos^2A/cos^2A

Cos^3A-(sin^2A+cos^2A)cos^2A

Cos^3A-1/cos^2A

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