Question

sin(90-o) cos(90-o) sin(90-o)/tan(90-o)​

Answer 1

Answer:

As we know that,

sin(90

o

−θ)=cosθ, cos(90

o

−θ)=sinθ,

cosec(90

o

−θ)=secθ, cot(90

o

−θ)=tanθ,

sec(90

o

−θ)=cosecθ, tan(90

o

−θ)=cotθ

∴

cosec(90−θ)sin(90−θ)cot(90−θ)

cos(90−θ)sec(90−θ)tanθ

+

cotθ

tan(90−θ)

∴

sin(90−θ)

1

×sin(90−θ)×tanθ

sinθ×

cos(90−θ)

1

×tanθ

+

cotθ

cotθ

=

cosθ

1

×cosθ

sinθ×

sinθ

1

+1

=1+1=2