Math, asked by SATYAM590, 1 year ago

Sin(90-theta)/1+sin theta+cos theta/1-cos(90-theta

Answers

Answered by Varun151
8
=sin (90-theta)/1+sintheta+costheta /1-cos (90-theta)
=cos theta / 1+sintheta + costheta / 1-sintheta =(costheta(1-sintheta) + costheta(1+sintheta))/1-sin^2 theta
= (costheta -sinthetacostheta +costheta+sinthetacostheta) / cos^2 theta
= 2 costheta / cos^2 theta
= 2 / costheta
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