Sin(90-theta)cos(90-theta)= tan theta / 1+tan ^2 theta
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Step-by-step explanation:
cos theta sin theta= tan theta/1+tan²theta
RHS
=tan thata/1+tan²theta
=tan theta/sec²theta [ 1+tan²theta=sec²theta]
=sin theta/cos theta×cos² theta
=sin theta .cos theta
LHS
hence,proved
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