Question

sin (90- theta) cot (90- theta) =1/sec(90-theta)​

Answer 1

Answer:

proved.

Using the equalities;

sin(90°-∅)=cos∅

cot(90°-∅)=tan∅

sec(90°-∅)=cosec∅

LHS:

=sin(90°-∅).cot(90°-∅)

=cos∅×tan∅

=cos∅×(sin∅/cos∅)

=sin∅

RHS:

=1/sec(90°-∅)

=1/cosec∅

=sin∅

Hence,LHS = RHS