Question

sin (90-theta) sin theta / tan theta + cos (90-theta) cos theta / cot theta

image for clear question:
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Answer 1

Answer:

As we know that,

sin(90o−θ)=cosθ, cos(90o−θ)=sinθ,

cosec(90o−θ)=secθ, cot(90o−θ)=tanθ,

sec(90o−θ)=cosecθ, tan(90o−θ)=cotθ

∴ cosec(90−θ)sin(90−θ)cot(90−θ)cos(90−θ)sec(90−θ)tanθ+cotθtan(90−θ)

∴ sin(90−θ)1×sin(90−θ)×tanθsinθ×cos(90−θ)1×tanθ+cotθcotθ

=cosθ1×cosθsinθ×sinθ1+1 

=1+1=2

Answer 2

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