Question

sin (90°-A)/ cosec (90°-A) + cos (90°-A)/ sec (90°- A)​

Answer 1

Answer:

1

Step-by-step explanation:

$\frac{sin(x)}{cosec(x)} = {(sin(x))}^{2}$

$\frac{cos(x)}{sec(x)} = {(cos(x))}^{2}$

add the above two equations to get the result