Math, asked by saravanan3949, 11 months ago

(sin 90° + cos 60° + cos 45º) (sin 30° + cos 0° - COS 45°) full steps please hurry​

Answers

Answered by tejasvinitha
2

Answer:

check the attachment refer trigonometric table for values

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Answered by monadasora03
1

Answer:

Sin 90= 1

cos 60=1/2

Cos 45=1/√2

Sin 30=1/2

Cos 0=1

(1+ 1/2+1/√2) (1/2+1-1/√2)

[(2+1+ √2)/2] [(1+2-√2)/2]

(3+√2)/2 x (3-√2)/2 { (a+b)(a-b)=a^2 - b^2}

(9- 2)/4

7/4

Step-by-step explanation:

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