Question

sin(90°−θ)cos(90°−θ)/

tanθ

= 1 − sin2θ​

Answer 1

Step-by-step explanation:

$\frac{ \sin(90 - x) \cos(90 - x) }{ \tan( x) } = \frac{ \cos(x) \sin(x) }{ \frac{ \sin(x) }{ \cos(x) } }$

$= \cos(x) \sin(x) \times \frac{ \cos(x) }{ \sin(x) }$

$= {cos}^{2} x$

${cos}^{2} x - 1 = sin2x$

${cos}^{2} x = 1 - sin2x$

Answer 2

We should follow the reduction formula to solve this question.

Sin(90-x) =cos(x)

Cos(90-x)= sin(x)

I have attached the answer.

Hope you understood how to solve the question.