Question

sin(90° − θ) ×cot(90°-θ) /sinθ+cos(90°-θ)=1/2​

Answer 1

Answer:

$\sin(90 - \theta \: ) = \cos( \theta) \\ \\ \cot(90 - \theta) = \tan( \theta) \\ \\ \cos(90 - \theta) = \sin( \theta)$

sin(90° − θ) ×cot(90°-θ) /sinθ+cos(90°-θ)=1/2

$= \frac{ \frac{\cos( \theta) }{1} \times \frac{ \sin( \theta) }{ \cos( \theta) } }{ \sin( \theta) + \sin( \theta) } \\ = \frac{\sin( \theta) }{ \: 2\sin( \theta) } \\ = \frac{1}{2}$

Answer 2

can u post the pic clearly.........