Math, asked by sandip191, 1 year ago

sin (90°- theta) cos (90°- theta) = tan theta/ 1+tan2 theta

Answers

Answered by Dhinu
4
hope it helps. .... :)
Attachments:
Answered by MunuThapa
5
L.H.S
sin ( 90°- theta) cos ( 90° - theta)
sin theta × cos theta
= 1
R.H.S
tan theta / 1+ tan² theta
= tan theta / sec ² theta
= sin theta / cos theta / sec² theta
= sin ² theta/ sec ² theta
= sin² theta × cos ² theta
= sin ² theta × 1/ sin² theta
= 1
L.H.S =R.H.S. Proved


Similar questions