Math, asked by suyashbh4, 6 months ago

Sin A = 1/3

Evaluate=
Cos A x Cosec A + tan A x Sec A​

Answers

Answered by DEBOBROTABHATTACHARY
2

Answer:

=16√2 + 3 /8

Step-by-step explanation:

sin a = 1/3

BC/AC = 1/3

BC = 1

AC = 3

By pythagoras property,

(AC)₂ = (AB)₂ + (BC)₂

[3]² = (AB)₂ + (1)₂

(AB)₂ = 9-1

= 8

AB.=√8 =2√2

cosA cosecA + tanA secA

= 2√2/3×3 + 1/2√2×3/2√2

=16√2 + 3 /8

Answered by MohanReddySathineni
0

Answer:

16√2+3/8

Step-by-step explanation:

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