Math, asked by vjJz, 20 days ago



sin A /1 + cos A
+
1+cos A /sin A
(A) 2 tan A
(B) 2 cota
(C) 2 sin A
(D) 2 cosecA​

Answers

Answered by beauty9090
0

Answer:

D. 2 cosecA

Step-by-step explanation:

={sin²A+(1+cosA)²/(1+cosA)sinA}

=sin²A+1+cos²A+2cosA/(1+cosA)SinA

=1+1+2cosA/(1+cosA)sinA

=2(1+cosA)/(1+cosA)sinA

=2cosecA

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