Math, asked by shubhamsharma065, 9 months ago

sin A / 1 - cos A+ cos A/ 1 - tanA= sinA+ cosA​

Answers

Answered by brainlyuser1218
0

Answer:

 \frac{ \sin(a) }{1 -  \cos }  +  \frac{ \cos(a) }{1 -  \tan(a) } =  \sin(a)  +  \cos(a)  \\  \\  \frac{ \sin(a) }{ \sin(a) }  + 1 -  \frac{ \sin(a) }{  \cos(a) }  =  \sin(a )  +  \frac{1}{ \sin(a) }  \\  \\  \frac{ \sin(a \cos(a +) )  +  \sin(a \cos(a) ) +  \ {}^{2} sin {}^{2}   }{ \sin(a \cos(a) ) }  =  \frac{? { \sin } ^{2}  a + 1 }{ \sin(a) }  \\  \\   \frac{ { \sin }^{2} a +  { \cos}^{2} a  +  { \sin}^{2} a}{? \sin(a \cos(a) ) }  =

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