(sin A+1+cos A)(sinA+cosA-1) secAcosecA =2
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LHS=(sinA+1+cosA)(sinA-1+cosA)secA*CosecA. =[(sinA+cosA)+1][sinA+cosA-1]secA*cosecA
=[(sinA+cosA)^2-(1)^2]secA*cosecA
=(sin^2A+2sinA*cosA+cos^2A-1)secA*cosecA
=[(sin^2A+cos^2A)+2sinA*cosA-1]secA*cosecA
=(1+2sinA*cosA-1)secA*cosecA
=2sinA*cosA*secA*cosecA
=2sinA*cosA*(1/sinA)*(1/cosA)
=2=RHS proved
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