Math, asked by preethi6916, 1 year ago

sin(a)/1-cos(a)+tan(a)/1+cos(a)=cot(a)+sec(a)-cosec(a)​

Answers

Answered by HARISHKABILAN
2

Explanation:

sin

θ

1

cos

θ

+

tan

θ

1

+

cos

θ

=

sin

θ

(

1

+

cos

θ

)

(

1

cos

θ

)

(

1

+

cos

θ

)

+

tan

θ

(

1

cos

θ

)

(

1

+

cos

θ

)

(

1

cos

θ

)

=

sin

θ

(

1

+

cos

θ

)

1

cos

2

θ

+

tan

θ

(

1

cos

θ

)

1

cos

2

θ

=

sin

θ

(

1

+

cos

θ

)

sin

2

θ

+

sin

θ

(

1

cos

θ

)

cos

θ

sin

2

θ

=

1

+

cos

θ

sin

θ

+

1

cos

θ

cos

θ

sin

θ

=

1

sin

θ

+

cos

θ

sin

θ

+

1

cos

θ

sin

θ

1

sin

θ

=

csc

θ

+

cot

θ

+

sec

θ

csc

θ

csc

θ

=

sec

θ

csc

θ

+

cot

θ


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