Question

sin A =1 / root 2 in right angle abc at C find the value of tan a tan b and cosec b​

Answer 1

Answer:

tan A • tan B = 1

cosec B = √2

Step-by-step explanation:

Given,

sinA = 1/√2

⇒ A = sin-¹[1/√2] = 45°

Since ABC is a right triangle, C is right angle, ∠A = 45°

∠A + ∠B + ∠C = 180° [Angle Sum Property of Triangles]

45° + ∠B + 90° = 180°

⇒ ∠B = 45°

So, tan A • tan B = tan45 • tan45 = 1 × 1 = 1

cosec B = cosec 45° = √2