sin A =1 / root 2 in right angle abc at C find the value of tan a tan b and cosec b
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Answer:
tan A • tan B = 1
cosec B = √2
Step-by-step explanation:
Given,
sinA = 1/√2
⇒ A = sin-¹[1/√2] = 45°
Since ABC is a right triangle, C is right angle, ∠A = 45°
∠A + ∠B + ∠C = 180° [Angle Sum Property of Triangles]
45° + ∠B + 90° = 180°
⇒ ∠B = 45°
So, tan A • tan B = tan45 • tan45 = 1 × 1 = 1
cosec B = cosec 45° = √2
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