Question

sin a ( 1+tan a) + cos a (1+ cot a ) = sec a+ cosec a​

Answer 1

Step-by-step explanation:

sina(1+tana)+cosa(1+cota)

=sina(cosa+sina/cosa)+cosa(sina+cosa/sina)

=(sina+cosa){sina/cosa+cosa/sina}

=(sina+cosa)(1/sinacosa)

=1/cosa+1/sina

=seca+coseca