Math, asked by jyotishjeeya6038, 11 months ago

Sin A (1+tan A ) +cos A (1+cotA) =secA+cosecA

Answers

Answered by sandy1816

3

Step-by-step explanation:

sinA(1+tanA)+cosA(1+cotA)

=sinA(cosA+sinA/cosA)+cosA(sinA+cosA/sinA)

=(sinA+cosA)(sinA/cosA+cosA/sinA)

=(sinA+cosA)(1/sinAcosA)

=1/cosA+1/sinA

=secA+cosecA

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