Math, asked by warmachine6205, 10 months ago

Sin a =15/17,cos b=12/13 thsnsin(a+b)

Answers

Answered by kritanuchatterjee280
1

Answer:

Step-by-step explanation:

Sin A = 15/17

Cos B = 12/13

Sin A = perpendicular/hypotenuse

Let us find the base for the first triangle,

By the Pythagoras Theorem,

h² = b²+p²

therefore, b²=h²-p²

b=root(289-225)

b=root(64)

b=8

Cos A = 8/17

Now in the second triangle,

cos B=12/13 = base/hypotenuse

Now finding perpendicular,

p=root(169-144)

p=root(25)

p=5

sin B=5/13

Sin (A+B) = SinACosB+CosASinB

= 15/17 * 12/13+ 8/17 * 5/13

= 180/221 + 40/221

= 220/221 is the answer

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