Sin a =15/17,cos b=12/13 thsnsin(a+b)
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Answer:
Step-by-step explanation:
Sin A = 15/17
Cos B = 12/13
Sin A = perpendicular/hypotenuse
Let us find the base for the first triangle,
By the Pythagoras Theorem,
h² = b²+p²
therefore, b²=h²-p²
b=root(289-225)
b=root(64)
b=8
Cos A = 8/17
Now in the second triangle,
cos B=12/13 = base/hypotenuse
Now finding perpendicular,
p=root(169-144)
p=root(25)
p=5
sin B=5/13
Sin (A+B) = SinACosB+CosASinB
= 15/17 * 12/13+ 8/17 * 5/13
= 180/221 + 40/221
= 220/221 is the answer
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