Math, asked by darshan9823, 11 months ago

sin A +2 sin3A + sin 5A÷sin 3A + 2 sin 5A + sin 7A=sin3A/sin5A​

Answers

Answered by raj8000
3

Step-by-step explanation:

=2sin2AcosA+2sin4AcosA/

2sin4AcosA+2sin6AcosA

=2sin3AcosA/2sin5AcosA

=sin3A/sin5A

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