Math, asked by hell17, 1 year ago

Sin(A/2)ssin(7A/2)+sin(3A/2)sin(11A/2)=sin2Asin5A

Answers

Answered by amt54321
0

Answer:

s = (sin(2) sin^(-1)(5 A) - sin((3 A)/2) sin((11 A)/2)) csc(A/2) csc((7 A)/2)

Step-by-step explanation:

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