Question

sin A =24/25 THEN cot A ​

Answer 1

$\huge\fcolorobox{black}{lime}{AnsweR:}$

Hi!

SinA = 24/25

We know that,

SinA = Opposite side(o) / Hypotenuse(h)

o/h = 24/25

Let the hypotenuse(AC) be "25k" and one of the sides(BC) be "24k"

BY Pythagoras theorem,

AB² + BC² = AC²

AB² = AC²-BC²

      = (25k)² - (24k)²

      = 625k² - 576k²

      = 49k²

AB = √49k²

     = 7k

AB = adjacent side(a)

We know that.

cotA = a/o

       = 7/24

cot A = 7/24 .

       

Answer 2

Answer:

\huge\fcolorobox{black}{lime}{AnsweR:}

Hi!

SinA = 24/25

We know that,

SinA = Opposite side(o) / Hypotenuse(h)

o/h = 24/25

Let the hypotenuse(AC) be "25k" and one of the sides(BC) be "24k"

BY Pythagoras theorem,

Step-by-step explanation:

AB² + BC² = AC²

AB² = AC²-BC²

      = (25k)² - (24k)²

      = 625k² - 576k²

      = 49k²

AB = √49k²

     = 7k

AB = adjacent side(a)

We know that.

cotA = a/o

       = 7/24