Question

sin(A+2B)=root3/2andcos(A+4B)=0 find angle AandB

Answer 1

hope it will help u

Answer 2

sin(A+2B)=√3/2=sin 60°
cos(A+4B)=0=cos 90°
A+2B=60°______1
A+4B=90°______2
2-1
2B=30°
B=15°
A=60°-2(15°)
=60°-30°
=30°
Ans: A = 30° B=15°