Question

sin (A+2B)=route 3 by two and cos (A+4B) = 0. Find A and B.​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

30 , 15

Step-by-step explanation:

sin (A+2B)= √(3/2)

(A+2B) = sin inverse of (√(3/2))

(A+2B) = 60

cos (A+4B) = 0

(A+4B) = cos inverse of 0

(A+4B) = 90

(A+2B) = 60

(A+4B) = 90

solving these to equations,

subtracting,

(A+2B) = 60

-[(A+4B) = 90]

-2B = -30

B = 15

therefore A = 90 -4 B = 30