Question

Sin A-2sin^3 A =tan A
___________
2cos^3 A -cos A

Answer 1

this is the process of your question

Answer 2

Answer:

Take common sinA from numerator and cosA from denominator

Then it will be in numerator sinA[ 1-2sin^2A] in denominator cosA [ 2cos^2A-1]

Now write sin^2A in numerator as 1-cos^2A

Now multiply it by 2 because it was with cos^2A

It will give sinA[1-2+2cos^A]/cosA[-1+2cos^2 A]

Now it will cut and sinA/cosA will left which is equal to tanA