Math, asked by rashi11236, 6 hours ago

sin A-2sin³A/2 cos³A-CosA

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Answered by deviamita679

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Answer:

sinA-2sin3A2cos3A-cosA

=sinA(1-2sin2A)cosA(2cos2A-1)

=sinA(sin2A+cos2A-2sin2A)cosA(2cos2A-sin2A-cos2A)

=sinA(cos2A-sin2A)cosA(cos2A-sin2A)

=sinAcosA

=tanA

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