sin A=√3/2,sin B=1, then find sin (B-A)?
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Answer:
sin(B-A)=1/2
Step-by-step explanation:
sin A=√3/2
sin A=sin 60
A=60
sin B=1
sin B=sin 90
B=90
sin(B-A)=sin(90-60)
=sin 30
=1/2
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sin A=√3/2,sin B=1, then find sin (B-A)?
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