Math, asked by vkeshava885, 9 months ago

sin A=√3/2,sin B=1, then find sin (B-A)?​

Answers

Answered by gnagamokshi
4

Answer:

sin(B-A)=1/2

Step-by-step explanation:

sin A=√3/2

sin A=sin 60

A=60

sin B=1

sin B=sin 90

B=90

sin(B-A)=sin(90-60)

            =sin 30

            =1/2

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Answered by mouryaraj047
0

sin A=√3/2,sin B=1, then find sin (B-A)?

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